1/3m^2=-1/6m+1/2

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Solution for 1/3m^2=-1/6m+1/2 equation: 


m in (-oo:+oo)

(1/3)*m^2 = (-1/6)*m+1/2 // - (-1/6)*m+1/2

(1/3)*m^2-((-1/6)*m)-(1/2) = 0

(1/3)*m^2+(1/6)*m-1/2 = 0

1/3*m^2+1/6*m-1/2 = 0

DELTA = (1/6)^2-(-1/2*1/3*4)

DELTA = 25/36

DELTA > 0

m = ((25/36)^(1/2)-1/6)/(1/3*2) or m = (-(25/36)^(1/2)-1/6)/(1/3*2)

m = 1 or m = -3/2

m in { -3/2, 1 }

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